pranab223 wrote:

IlCreatore wrote:

I tried to plug-in some numbers but I don't get the right answer. Anyone willing to show his/her try?

QTY A

SInce change in BMI increased by 1

Therefore change in weight =\(\frac{h^2}{703} * change in BMI\)

= \(\frac{74^2}{703}* 1\)

= \(\frac{5476}{703}\)

Therefore change in weight =\(\frac{h^2}{703} * change in BMI\)

= \(\frac{65^2}{703}* 1.2\)

= \(\frac{5070}{703}\)

Therefore QTY A> QTY B (since denominator are same in both qty)

Since we don't know the change in weight, shouldn't the answer be D?

Say the Change in weight for Quantity A is 100 and for Quantity B is 200.

\(\frac{5476}{703} / 100 = \frac{5476}{7.03}\)

\(\frac{5070}{703} / 200 = \frac{5070}{3.015} = \frac{10,140}{7.03}\)

So Qty B is greater.

Ultimately the change in weight can be manipulated to make Quantity A greatere, or maybe even equal to B.