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# Bob’s pickup truck averages 20 miles/gallon. If Bob fills th

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Bob’s pickup truck averages 20 miles/gallon. If Bob fills th [#permalink]  03 Oct 2017, 20:42
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Bob’s pickup truck averages 20 miles/gallon. If Bob fills the 12-gallon gas tank to capacity, how many miles can he travel once the ratio of unused gas to used gas is 3:1?

(A) 60 miles

(B) 140 miles

(C) 170 miles

(D) 180 miles

(E) 240 miles

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Re: Bob’s pickup truck averages 20 miles/gallon. If Bob fills th [#permalink]  03 Oct 2017, 22:47
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Given he has filled his truck with 12 gallons, the unused gas is $$\frac{12}{4}*3 = 9$$, where 4 is the sum of the parts in the ratio and 3 the part unused.

Then, he can drive for $$9*20 = 180$$ miles more.

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Re: Bob’s pickup truck averages 20 miles/gallon. If Bob fills th [#permalink]  03 Oct 2017, 23:17
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Bunuel wrote:
Bob’s pickup truck averages 20 miles/gallon. If Bob fills the 12-gallon gas tank to capacity, how many miles can he travel once the ratio of unused gas to used gas is 3:1?

Let us consider Bob uses x gallons

Therefore we can set the ratio as -

$$\frac{(12-x)}{x} =\frac{3}{1}$$ (since 12 gallons is full tank and (12-x) is the unused gas)

or $$x= 3$$.

Now we have to consider in the ratio of $$\frac{3}{1}$$

i.e $$\frac{3x}{x} = \frac{9}{3}$$ (putting the value of x = 3, because we have assumed he uses x gallons and so in every 3parts used gas we have 9 parts unsed gas)

Therefore Bob can travel with 9 gallons remaining fuel = 9*20 = 180 miles
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Re: Bob’s pickup truck averages 20 miles/gallon. If Bob fills th   [#permalink] 03 Oct 2017, 23:17
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