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# b − 3, b − 1, b + 2, b + 3, b + 4

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Founder
Joined: 18 Apr 2015
Posts: 6874
Followers: 114

Kudos [?]: 1332 [0], given: 6293

b − 3, b − 1, b + 2, b + 3, b + 4 [#permalink]  28 Jan 2016, 13:24
Expert's post
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Question Stats:

60% (00:50) correct 40% (00:48) wrong based on 30 sessions
b − 3, b − 1, b + 2, b + 3, b + 4

The median of the ﬁve terms listed above is 5, where b is a constant. What is the average (arithmetic mean) of the ﬁve terms?

 A 3
 B 4
 C 5
 D 6
 E 7

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Question: 11
Page: 468
Difficulty: easy/medium
[Reveal] Spoiler: OA

_________________
Founder
Joined: 18 Apr 2015
Posts: 6874
Followers: 114

Kudos [?]: 1332 [0], given: 6293

Re: b − 3, b − 1, b + 2, b + 3, b + 4 [#permalink]  28 Jan 2016, 13:29
Expert's post
Solution

The median is the middle number in a set of odd numbers. As such, we do have from stem that $$b+2=5$$ so $$b=3$$

It follows that the values of the five terms are $$\frac{0+2+5+6+7}{5}=\frac{20}{5}=4$$

The answer is $$B$$
_________________
Intern
Joined: 08 Mar 2018
Posts: 11
Followers: 0

Kudos [?]: 8 [1] , given: 10

Re: b − 3, b − 1, b + 2, b + 3, b + 4 [#permalink]  27 Mar 2018, 08:51
1
KUDOS
the answer key in the original question is wrong. Correct answer should be B (4)
Founder
Joined: 18 Apr 2015
Posts: 6874
Followers: 114

Kudos [?]: 1332 [0], given: 6293

Re: b − 3, b − 1, b + 2, b + 3, b + 4 [#permalink]  27 Mar 2018, 09:42
Expert's post
Thank you. We had a mismatch when updated the questions with the new timer.

Regards
_________________
Re: b − 3, b − 1, b + 2, b + 3, b + 4   [#permalink] 27 Mar 2018, 09:42
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