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# At the rate of

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At the rate of [#permalink]  06 Jul 2019, 09:47
Expert's post
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Question Stats:

62% (01:15) correct 37% (01:25) wrong based on 66 sessions
At the rate of $$\frac{x}{6}$$ miles for every y seconds, how many miles can an aircraft travel in z minutes? $$(xyz \neq 0)$$

A. $$\frac{xy}{6z}$$

B. $$\frac{xz}{6y}$$

C. $$\frac{xyz}{6}$$

D. $$\frac{10xy}{z}$$

E. $$\frac{10xz}{y}$$
[Reveal] Spoiler: OA

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Re: At the rate of [#permalink]  07 Jul 2019, 05:08
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Expert's post
Carcass wrote:
At the rate of $$\frac{x}{6}$$ miles for every y seconds, how many miles can an aircraft travel in z minutes? $$(xyz \neq 0)$$

A. $$\frac{xy}{6z}$$

B. $$\frac{xz}{6y}$$

C. $$\frac{xyz}{6}$$

D. $$\frac{10xy}{z}$$

E. $$\frac{10xz}{y}$$

We can solve this question with equivalent ratios

First recognize that z MINUTES = 60z SECONDS (since there are 60 seconds in every minute

We're told that the aircraft travels x/6 miles every y seconds
In other words, for every y seconds that elapse, the aircraft travels x/6 miles

Let D = the distance the aircraft travels 60z seconds.

We'll use the ratio: distance traveled/seconds elapsed

We get: (x/6)/y = D/60z
Cross multiply to get: Dy = (x/6)(60z)
Simplify: Dy = 10xz
Divide both sides by y to get: D = 10xz/y

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Re: At the rate of   [#permalink] 07 Jul 2019, 05:08
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# At the rate of

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