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At the rate of

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Founder
Founder
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Joined: 18 Apr 2015
Posts: 13892
GRE 1: Q160 V160
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Kudos [?]: 3676 [0], given: 12919

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At the rate of [#permalink] New post 06 Jul 2019, 09:47
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Question Stats:

62% (01:15) correct 37% (01:25) wrong based on 66 sessions
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Kudos [?]: 4766 [3] , given: 70

Re: At the rate of [#permalink] New post 07 Jul 2019, 05:08
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Carcass wrote:
At the rate of \(\frac{x}{6}\) miles for every y seconds, how many miles can an aircraft travel in z minutes? \((xyz \neq 0)\)

A. \(\frac{xy}{6z}\)

B. \(\frac{xz}{6y}\)

C. \(\frac{xyz}{6}\)

D. \(\frac{10xy}{z}\)

E. \(\frac{10xz}{y}\)


We can solve this question with equivalent ratios

First recognize that z MINUTES = 60z SECONDS (since there are 60 seconds in every minute

We're told that the aircraft travels x/6 miles every y seconds
In other words, for every y seconds that elapse, the aircraft travels x/6 miles

Let D = the distance the aircraft travels 60z seconds.

We'll use the ratio: distance traveled/seconds elapsed

We get: (x/6)/y = D/60z
Cross multiply to get: Dy = (x/6)(60z)
Simplify: Dy = 10xz
Divide both sides by y to get: D = 10xz/y

Answer: E

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Re: At the rate of   [#permalink] 07 Jul 2019, 05:08
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