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# Assume the function f(x) is defined as follows: f(x) = (x

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Intern
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Kudos [?]: 17 [1] , given: 14

Assume the function f(x) is defined as follows: f(x) = (x [#permalink]  05 Jun 2016, 16:01
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Assume the function f(x) is defined as follows: $$f(x) = (x-4)^2 + \sqrt{(x+3)} + \frac{5}{x+2}$$. For Which of the following values of x is f(x) defined?

Indicate all such values.

A. -5
B. -4
C. -3
D. -2
E. -1

[Reveal] Spoiler:
C, E

Last edited by GreenlightTestPrep on 06 Jan 2019, 11:17, edited 3 times in total.
Renamed the topic and edited the question.
Founder
Joined: 18 Apr 2015
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Kudos [?]: 1344 [0], given: 6318

Expert's post
GREHelp what is the source of the question ???
_________________
Intern
Joined: 05 Jan 2016
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Kudos [?]: 17 [1] , given: 14

1
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Sorry the source of the question is Manhattan Prep Algebra Book.
Intern
Joined: 05 Jan 2016
Posts: 28
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Kudos [?]: 17 [1] , given: 14

1
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Can anyone provide any guidance to help answer this?
Senior Manager
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Kudos [?]: 50 [4] , given: 220

Re: Assume the function f(x) is defined as follows: f(x) = (x [#permalink]  10 Jun 2016, 13:55
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GREhelp wrote:
Assume the function f(x) is defined as follows: $$f(x) = (x-4)^2 + \sqrt{(x+3)} + \frac{5}{x+2}$$. For Which of the following values of x is f(x) defined?

Indicate all such values.

A. -5
B. -4
C. -3
D. -2
E. -1

The answer is C and E. I could only select one in the official answer choice box.

You should know two properties:

1. The square root from a negative number is not defined, thus x+3 must be more than or equal to 0: $$x+3 \geq 0$$ --> $$x \geq-3$$. Eliminate options A, and B.

2. Division by 0 is not allowed, thus x+2 cannot be 0, which means that x cannot be -2. Eliminate D.

Hope it's clear.
Intern
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Kudos [?]: 4 [1] , given: 2

Re: Assume the function f(x) is defined as follows: f(x) = (x [#permalink]  24 Jul 2017, 07:20
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Great, thanks
Re: Assume the function f(x) is defined as follows: f(x) = (x   [#permalink] 24 Jul 2017, 07:20
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