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Angle BAD = y, Angle BAC = z, Angle ABC = x, and Angle ACB [#permalink]
03 Dec 2018, 04:39
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∠BAD = y°, ∠BAC = z°, ∠ABC = x°, and ∠ACB = w°
Quantity A 
Quantity B 
x + w 
y + z 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given




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Re: Given Angle BAD = y, Angle BAC = Z [#permalink]
03 Dec 2018, 11:22
No, mainly because we do have all the questions explained here https://greprepclub.com/forum/official ... html#p3207And I didn't see this question before. Regards
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Re: Given Angle BAD = y, Angle BAC = Z [#permalink]
03 Dec 2018, 11:29
Carcass wrote: No, mainly because we do have all the questions explained here https://greprepclub.com/forum/official ... html#p3207And I didn't see this question before. Regards That too It's a great question either way!
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Re: Given Angle BAD = y, Angle BAC = Z [#permalink]
03 Dec 2018, 11:43
Sir, please give us some explanation to this question, if you can. Meanwhile, I will edit the main post. Thank you so much. Regards
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Re: Angle BAD = y, Angle BAC = z, Angle ABC = x, and Angle ACB [#permalink]
03 Dec 2018, 12:43
The answer is A right? Sum of two angles in a triangle is greater than the third angle



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Re: Angle BAD = y, Angle BAC = z, Angle ABC = x, and Angle ACB [#permalink]
03 Dec 2018, 15:32
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Arun1992 wrote: ∠BAD = y°, ∠BAC = z°, ∠ABC = x°, and ∠ACB = w°
Quantity A 
Quantity B 
x + w 
y + z 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given Let's test some possible values (angles) Case i: In the above case, y = 70, z = 110, x = 40 and w = 30 So, we get: QUANTITY A: x + w = 40 + 30 = 70 QUANTITY B: y + z = 70 + 110 = 180 In this case, Quantity B is greater Case ii: In the above case, y = 40, z = 50, x = 70 and w = 60 So, we get: QUANTITY A: x + w = 70 + 60 = 130 QUANTITY B: y + z = 40 + 50 = 90 In this case, Quantity A is greaterAnswer: D Cheers, Brent
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Re: Angle BAD = y, Angle BAC = z, Angle ABC = x, and Angle ACB [#permalink]
03 Dec 2018, 15:34
kruttikaaggarwal wrote: The answer is A right? Sum of two angles in a triangle is greater than the third angle Great idea but, unfortunately, that's not a rule. I believe you're taking the rule regarding side LENGTHS in a triangle and extending it to work with ANGLES (which doesn't work). Cheers, Brent
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Re: Given Angle BAD = y, Angle BAC = Z [#permalink]
03 Dec 2018, 15:35
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Carcass wrote: Sir,
please give us some explanation to this question, if you can. Meanwhile, I will edit the main post.
Thank you so much.
Regards Done!
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Re: Angle BAD = y, Angle BAC = z, Angle ABC = x, and Angle ACB [#permalink]
03 Dec 2018, 22:24
GreenlightTestPrep wrote: Arun1992 wrote: ∠BAD = y°, ∠BAC = z°, ∠ABC = x°, and ∠ACB = w°
Quantity A 
Quantity B 
x + w 
y + z 
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given Let's test some possible values (angles) In the above case, y = 70, z = 110, x = 40 and w = 30 So, we get: QUANTITY A: x + w = 40 + 30 = 70 QUANTITY B: y + z = 70 + 110 = 180 In this case, Quantity B is greater In the above case, y = 40, z = 50, x = 70 and w = 60 So, we get: QUANTITY A: x + w = 70 + 60 = 130 QUANTITY B: y + z = 40 + 50 = 90 In this case, Quantity A is greaterAnswer: D Cheers, Brent Hi @GreenlightTestPrep Thanks a lot for ur explanation. But can u tell me how did u pick the correct angles to check. Is there any logic behind it ?



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Re: Angle BAD = y, Angle BAC = z, Angle ABC = x, and Angle ACB [#permalink]
17 Dec 2018, 20:25
Just think about this, since we don't have ANY number associated with any of the angles, it's a total crapshoot. for all we know, it could be a scalene triangle, where x and w are 10 degrees each while y and z total to 160, or the complete opposite.




Re: Angle BAD = y, Angle BAC = z, Angle ABC = x, and Angle ACB
[#permalink]
17 Dec 2018, 20:25





