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An airport conveyor belt is 120 meters long, and moves at a [#permalink]
26 Oct 2017, 02:25

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Question Stats:

0% (00:00) correct
100% (01:32) wrong based on 1 sessions

An airport conveyor belt is 120 meters long, and moves at a constant rate of 2m/s. A man carrying two suitcases walks at a constant rate of 4m/s. How long will it take him to cross from one end of the conveyor belt to the other, if the man only walks for half the time he is on the conveyor belt?

A. 25 seconds B. 30 seconds C. 42 seconds D. 45 seconds E. 54 seconds

Re: An airport conveyor belt is 120 meters long, and moves at a [#permalink]
27 Oct 2017, 12:19

1

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For half the time the man is standing still. So he is moving at a speed of 2 m/s. For the other half, the man is moving walking and the belt is moving so his effective speed is 2 + 4 = 6 m/s So his average speed = (2 + 6)/2 = 4 m/s (Avg speed is the avg of two speeds when time taken is equal)

Time taken = Distance/Avg speed = 120/4 = 30 sec (Option B is the answer.)

greprepclubot

Re: An airport conveyor belt is 120 meters long, and moves at a
[#permalink]
27 Oct 2017, 12:19