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# Among the 9,000 people attending a football game at College

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Founder
Joined: 18 Apr 2015
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Kudos [?]: 2998 [1] , given: 11253

Among the 9,000 people attending a football game at College [#permalink]  12 Dec 2015, 08:00
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Question Stats:

71% (00:37) correct 28% (00:46) wrong based on 241 sessions
Among the 9,000 people attending a football game at College C, there were x students from College C and y students who were not from College C

 Quantity A Quantity B The number of people attending the game who were not students 9,000 − x − y

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Practice Questions
Question: 5
Page: 151
Difficulty: medium
[Reveal] Spoiler: OA

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Founder
Joined: 18 Apr 2015
Posts: 12020
Followers: 254

Kudos [?]: 2998 [2] , given: 11253

Re: Among the 9,000 people attending a football game at College [#permalink]  12 Dec 2015, 08:08
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Expert's post
Solution

We do have 9000 splits into 3 parts: students from C, students NOT from C , and not students at all.

We can name them as $$x+y+z=9000$$

So $$z= 9000 - x - y$$

So the best answer is $$C$$
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GRE Instructor
Joined: 10 Apr 2015
Posts: 3532
Followers: 133

Kudos [?]: 3995 [2] , given: 65

Re: Among the 9,000 people attending a football game at College [#permalink]  09 Jun 2018, 05:36
2
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Expert's post
Carcass wrote:
Among the 9,000 people attending a football game atCollege C, there were x students from College C and y students who were not from College C

 Quantity A Quantity B The number of peopleattending the game whowere not students 9,000 − x − y

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Practice Questions
Question: 5
Page: 151
Difficulty: medium

Another approach is to use the Double Matrix Method. This technique can be used for most questions featuring a population in which each member has two characteristics associated with it (aka overlapping sets questions).
Here, we have a population of people watching a football game, and the two characteristics are:
- from College C or not from College C
- student or non student

We can set up out diagram as follows:

Since the two columns (student and non-student) must add to 9000, the SUM of the two boxes in the non-student column must = 9000 - (x + y)
= 9000 - x - y

So, we get:
Quantity A: 9000 - x - y
Quantity B: 9000 - x - y

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Intern
Joined: 15 May 2018
Posts: 38
Followers: 0

Kudos [?]: 6 [0], given: 1

Re: Among the 9,000 people attending a football game at College [#permalink]  09 Jul 2018, 18:33
Carcass wrote:
Among the 9,000 people attending a football game atCollege C, there were x students from College C and y students who were not from College C

 Quantity A Quantity B The number of peopleattending the game whowere not students 9,000 − x − y

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Practice Questions
Question: 5
Page: 151
Difficulty: medium

Manager
Joined: 23 Oct 2018
Posts: 57
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: Among the 9,000 people attending a football game at College [#permalink]  25 Oct 2018, 21:41
Intern
Joined: 29 Oct 2019
Posts: 3
Followers: 0

Kudos [?]: 0 [0], given: 5

Re: Among the 9,000 people attending a football game at College [#permalink]  17 Nov 2019, 14:55
In a question like this, would it be possible for the number of students not from college C to be 0? (Kind of as a trick question)
Founder
Joined: 18 Apr 2015
Posts: 12020
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Kudos [?]: 2998 [0], given: 11253

Re: Among the 9,000 people attending a football game at College [#permalink]  19 Nov 2019, 07:19
Expert's post
No. Impossible.

The question then would not make any sense.

Regards
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Re: Among the 9,000 people attending a football game at College   [#permalink] 19 Nov 2019, 07:19
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