Carcass wrote:
Alice and David are two of the ten people in a group. In how many different ways can this group of 10 people be divided into a group of 7 people and a group of 3 people if Alice and David are to be in the same group?
A. 48
B. 56
C. 64
D. 80
E. 128
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Let us consider the first the group of 7,
If DAvid and Alice are in this group then we need to choose only 5 out of 7 from total of 8 people(as David and Alice are considered in the group)
so we have 8C5 = 56 ways.
Now if David and Alice are in the group of 3 people then selecting the group from the total of 8 people will be = 8C1 = 8
So the total no. of ways = 56 + 8 = 64 ways
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53% (01:18) correct
