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ABCD and EFGH are rectangles. What is the area of the shaded

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ABCD and EFGH are rectangles. What is the area of the shaded [#permalink]  04 Mar 2017, 03:35
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#GREpracticequestion ABCD and EFGH are rectangles.jpg [ 8.85 KiB | Viewed 897 times ]

ABCD and EFGH are rectangles. What is the area of the shaded region?

A) 3$$x^2$$ — xy

B) 4$$x^2$$ — xy

C) 4$$x^2$$ — 2xy

D) 6$$x^2$$ — xy

E) 6$$x^2$$ — 2xy
[Reveal] Spoiler: OA

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Re: ABCD and EFGH are rectangles. What is the area of the shaded [#permalink]  07 Mar 2017, 16:07
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Expert's post
Explanation

Find the area of ABCD and EFGH:

Area = $$l \times w$$
Area of ABCD = $$3x \times 2x = 6x^2$$
Area of EFGH = $$x \times y = xy$$

The area of the shaded region is the area of ABCD minus the area of EFGH:

Area of ABCD = $$6x^2$$
Area of EFGH = $$xy$$

Area of the shaded region = $$6x^2 - xy$$

Hence option D is correct.
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Re: ABCD and EFGH are rectangles. What is the area of the shaded [#permalink]  14 Feb 2019, 08:16
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Carcass wrote:

Attachment:
#GREpracticequestion ABCD and EFGH are rectangles.jpg

ABCD and EFGH are rectangles. What is the area of the shaded region?

A) 3$$x^2$$ — xy

B) 4$$x^2$$ — xy

C) 4$$x^2$$ — 2xy

D) 6$$x^2$$ — xy

E) 6$$x^2$$ — 2xy

Shaded area = (area of rectangle ABCD) - (area of rectangle EFGH)

Area of rectangle = (base)(height)

We get: Shaded area = (3x)(2x) - (x)(y)
Simplify: Shaded area = 6x² - xy

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Re: ABCD and EFGH are rectangles. What is the area of the shaded   [#permalink] 14 Feb 2019, 08:16
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