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# abc < 0 and b^2c > 0

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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 111

Kudos [?]: 1854 [0], given: 397

abc < 0 and b^2c > 0 [#permalink]  30 Aug 2018, 16:34
Expert's post
00:00

Question Stats:

78% (00:40) correct 21% (01:05) wrong based on 14 sessions
$$abc < 0$$
$$b^2c > 0$$

 Quantity A Quantity B $$ab$$ $$0$$

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________

Sandy
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Manager
Joined: 29 Nov 2017
Posts: 190
Location: United States
GRE 1: Q142 V146
WE: Information Technology (Computer Software)
Followers: 0

Kudos [?]: 78 [0], given: 99

Re: abc < 0 and b^2c > 0 [#permalink]  01 Sep 2018, 07:25
abc<0abc<0
b2c>0

we need to regognise which of the number are negative. here only B is negative a is positive and the option B is correct.
Intern
Joined: 22 Aug 2018
Posts: 26
Followers: 0

Kudos [?]: 5 [0], given: 4

Re: abc < 0 and b^2c > 0 [#permalink]  01 Sep 2018, 07:46
IshanGre wrote:
abc<0abc<0
b2c>0

we need to regognise which of the number are negative. here only B is negative a is positive and the option B is correct.

I still did not understand this. Could you please elaborate somemore?
GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 111

Kudos [?]: 1854 [1] , given: 397

Re: abc < 0 and b^2c > 0 [#permalink]  01 Sep 2018, 15:02
1
KUDOS
Expert's post
We have $$abc<0$$ this means that either a, b , c or all three are negative. Since product of the three is negative.

Now $$b^2c>0$$. Since $$b^2$$ is always a positive number then $$c$$ must be a positive number for $$b^2c>0$$ to be true.

For $$abc<0$$ to be true $$ab<0$$ must be true, since c is a positive number.

Thus Quantity A, namely $$ab$$, is less than Quantity B, which is 0.
_________________

Sandy
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Re: abc < 0 and b^2c > 0   [#permalink] 01 Sep 2018, 15:02
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