Carcass wrote:
AB is parallel to CD.
AD is parallel to BC.
2AD = EG
Quantity A |
Quantity B |
The area of ABCD |
The area of EFG |
The given information tells us that ABCD is a parallelogram, which means the area = (base)(height)
Let x = the length of the base (AD)
We're told that L = the height of the parallelogram
So,
the area of ABCD = (x)(L)Area of triangle = (base)(height)/2
Given: 2AD = EG
We already let x = the length of AD
So, EG = 2x
In other words, the length of the triangle's base = 2x
We're told that L = the height of the triangle
So,
the area of triangle EFG = (L)(2x)/2 = (L)(x)We have:
Quantity A:
(x)(L)Quantity B:
(L)(x)Answer:
Cheers,
Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com
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