Carcass wrote:

A widow received \(\frac{1}{3}\) of her husband's estate, and each of her three sons received \(\frac{1}{3}\) of the balance. If 3 the widow and one of her sons received a total of $60,000 from the estate, what was the amount of the estate?

(A) $90,000

(B) $96,000

(C) $108,000

(D) $135,000

(E) $180,000

Let the total amount be = \(X\)

Now the widow received = \(\frac{1}{3} * X = \frac{X}{3}\)

The remaining balance =\(X -\frac{X}{3} = \frac{{2X}}{3}\)

and each son received = \(\frac{1}{3} * \frac{2X}{3} = \frac{2X}{9}\)

Therefore

\(\frac{X}{3} + \frac{2X}{9} = 60000\)

or \(5X = 60000 * 9\)

or \(X = \frac{{60000 * 9}}{5} = $108,000\)

Hence option C

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