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A widow received j of her husband's estate, and each of her [#permalink]
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Question Stats: 42% (01:35) correct 57% (01:10) wrong based on 7 sessions
A widow received $$\frac{1}{3}$$ of her husband's estate, and each of her three sons received $$\frac{1}{3}$$ of the balance. If 3 the widow and one of her sons received a total of $60,000 from the estate, what was the amount of the estate? (A)$90,000

(B) $96,000 (C)$108,000

(D) $135,000 (E)$180,000
[Reveal] Spoiler: OA

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Re: A widow received j of her husband's estate, and each of her [#permalink]
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Carcass wrote:
A widow received $$\frac{1}{3}$$ of her husband's estate, and each of her three sons received $$\frac{1}{3}$$ of the balance. If 3 the widow and one of her sons received a total of $60,000 from the estate, what was the amount of the estate? (A)$90,000

(B) $96,000 (C)$108,000

(D) $135,000 (E)$180,000

Let the total amount be = $$X$$

Now the widow received = $$\frac{1}{3} * X = \frac{X}{3}$$

The remaining balance =$$X -\frac{X}{3} = \frac{{2X}}{3}$$

and each son received = $$\frac{1}{3} * \frac{2X}{3} = \frac{2X}{9}$$

Therefore

$$\frac{X}{3} + \frac{2X}{9} = 60000$$

or $$5X = 60000 * 9$$

or $$X = \frac{{60000 * 9}}{5} = 108,000$$

Hence option C
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