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A train takes 15 seconds to cross a bridge at 50 mph, and at

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A train takes 15 seconds to cross a bridge at 50 mph, and at [#permalink] New post 30 Apr 2019, 01:26
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20% (02:55) correct 80% (01:59) wrong based on 5 sessions
A train takes 15 seconds to cross a bridge at 50 mph, and at the same speed takes 10 seconds to cross the same bridge when the train's length is halved.

Quantity A
Quantity B
Length of the bridge
Original length of the train


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: A train takes 15 seconds to cross a bridge at 50 mph, and at [#permalink] New post 02 May 2019, 11:08
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Solutions for this problem please?
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Re: A train takes 15 seconds to cross a bridge at 50 mph, and at [#permalink] New post 03 May 2019, 01:42
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Recall the key formula

Distance = speed * time

Now, we do have actually two distances.

Let the bridge being B and the train is L

The common factor here is the speed = 50

1) \(\frac{B+L}{15} = 50\)

\(\frac{B+\frac{L}{2}}{10} = 50\)

Equate the two \(\frac{B+L}{15} = \frac{B+\frac{L}{2}}{10}\)

\(2(B + L) = 3(B + \frac{L}{2})\)

\(2B + 2L = 3B + \frac{3L}{2}\)

\(\frac{L}{2} = B\)

\(L = 2B\)

The length of the train is twice the length of the bridge.

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Re: A train takes 15 seconds to cross a bridge at 50 mph, and at   [#permalink] 03 May 2019, 01:42
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A train takes 15 seconds to cross a bridge at 50 mph, and at

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