We can assume two values for score in the first and second test.

To make calculation simple

Let us say the student's score in the first test was 50 and in the second test was also 50. The average of the two test would be 50.

The question mentions that the student's score on the final test was 60% more than the average of the two tests.

Hence the final test score of the student was 50 * 1.6 = 80Now we need to find the average of the three tests because we have to compare this with the final test score.

Avg of the three tests = \(\frac{50 + 50 + 80}{3}\) = \(\frac{180}{3}\) =

60We have all the information needed to answer the question.

Therefore

final score/avg of three scores * 100 = the final score as a % of avg of the three scores.

\(\frac{80}{60}\) * \(100\) = \(133.33%\)

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This is my response to the question and may be incorrect. Feel free to rectify any mistakes