It is currently 24 Nov 2020, 12:14

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A rectangular public park has an area of 3,600 square feet.

Author Message
TAGS:
Retired Moderator
Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3033 [1] , given: 394

A rectangular public park has an area of 3,600 square feet. [#permalink]  27 May 2018, 12:22
1
KUDOS
Expert's post
00:00

Question Stats:

44% (01:41) correct 55% (02:33) wrong based on 29 sessions
A rectangular public park has an area of 3,600 square feet. It is surrounded on three sides by a chain link fence. If the entire length of the fence measures 180 feet, how many feet long could the unfenced side of the rectangular park be?

Indicate all such lengths.

A. 30
B. 40
C. 60
D. 90
E. 120
[Reveal] Spoiler: OA

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

Retired Moderator
Joined: 07 Jun 2014
Posts: 4803
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 175

Kudos [?]: 3033 [3] , given: 394

Re: A rectangular public park has an area of 3,600 square feet. [#permalink]  27 May 2018, 13:16
3
KUDOS
Expert's post
Explanation

The two values given are the area of the park and three out of the four sides of the perimeter of the park. If the side without fencing is a length, the equation for the overall length of the existing fence is 180 = 2W + L, so L = 180 – 2W.

The equation for the area of the park is LW = 3,600. With two variables and two equations, it is now possible to solve for the possible values of L:

$$L \times W = 3,600 L = 180 - 2W$$

$$(180 - 2W)W = 3,600$$

$$180W - 2W^2 = 3,600$$

$$90W - W^2 = 1,800$$

$$0 = W^2 - 90W + 1,800$$

$$0 = (W - 60)(W - 30)$$

So W = 30 or 60. Plug each value back into either of the original two equations to solve for the corresponding length, which is 120 or 60, respectively.
_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

Intern
Joined: 01 Jul 2020
Posts: 7
Followers: 0

Kudos [?]: 6 [0], given: 4

Re: A rectangular public park has an area of 3,600 square feet. [#permalink]  19 Jul 2020, 05:05
There is something wrong here. sandy's explanation is correct, but nowhere does the question say exactly which side of the park is left unfenced. It could well be either length or width of the park. If we consider only length, as sandy writes, sure it is either 120 or 60. But we also have to consider the possibility that the unfenced side is the width, which is either 30 or 60. Hence, 30 has got to be one of the possibilities. Surely, the answers are A, C, E?
Founder
Joined: 18 Apr 2015
Posts: 13891
GRE 1: Q160 V160
Followers: 313

Kudos [?]: 3676 [0], given: 12910

Re: A rectangular public park has an area of 3,600 square feet. [#permalink]  19 Jul 2020, 07:58
Expert's post
The spoiler says C and E
_________________
Re: A rectangular public park has an area of 3,600 square feet.   [#permalink] 19 Jul 2020, 07:58
Display posts from previous: Sort by