ExplanationThe best approach here is to Plug In.

First, try s = 2 and t = 3: Quantity A is (2 + 3)2 = 52 = 25, and Quantity B is 22 + 32 = 4 + 9 = 13.

Quantity A is greater, so eliminate choices (B) and (C). Next, make s and t both 0: Now Quantity A is \((0)^2 = 0\), and Quantity B is \(0^2 + 0^2 = 0\).

Now the two quantities are equal, so eliminate choice (A), and you’re left with choice (D).

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Sandy

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