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# A producer must select a duo, consisting of one lead actor

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Founder
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Kudos [?]: 1266 [1] , given: 5997

A producer must select a duo, consisting of one lead actor [#permalink]  27 Sep 2017, 14:16
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Expert's post
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Question Stats:

90% (00:30) correct 9% (00:35) wrong based on 11 sessions

A producer must select a duo, consisting of one lead actor and one supporting actor, from six candidates. What is the number of possible duos the producer could select?

[Reveal] Spoiler: OA
30

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Director
Joined: 20 Apr 2016
Posts: 864
WE: Engineering (Energy and Utilities)
Followers: 11

Kudos [?]: 645 [0], given: 141

Re: A producer must select a duo, consisting of one lead actor [#permalink]  27 Sep 2017, 22:07
Carcass wrote:
A producer must select a duo, consisting of one lead actor and one supporting actor, from six candidates. What is the number of possible duos the producer could select?

[Reveal] Spoiler: OA
30

Here it has asked for specific actors so we use the permutation formula $$\frac{n!}{(n-r)!}$$

$$\frac{6!}{(6-2)!}$$= 6x5 = 30
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Intern
Joined: 28 Mar 2018
Posts: 21
Followers: 1

Kudos [?]: 4 [0], given: 11

Re: A producer must select a duo, consisting of one lead actor [#permalink]  27 Apr 2018, 11:27
can someone please explain when to use permutation or combination methods?thanks in advance.
Founder
Joined: 18 Apr 2015
Posts: 6629
Followers: 107

Kudos [?]: 1266 [1] , given: 5997

Re: A producer must select a duo, consisting of one lead actor [#permalink]  27 Apr 2018, 23:38
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Expert's post
Permutations are for lists (order matters) and combinations are for groups (order doesn’t matter).

If you have to choose among 5 pizzas of a menu, two of them and it is a combination (which one you choose is irrelevant ) then you do have $$\frac{5*4*3*2*1}{2*1*3*2*1}$$.

Permutation the order matters. If you have to choose margherita as first choice and pepperoni as a second choice then you do have : $$5*4$$

Hope it helps

Regards
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Re: A producer must select a duo, consisting of one lead actor   [#permalink] 27 Apr 2018, 23:38
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