PLEASE CHANGE THE OA!OA of this question is B. Here's how:

Average Speed = Total Distance/Total Time

36 = (Distance of First part + Distance of Second part)/(Time for first part + time for second)

36 = (30t1 + 40t2)/(t1 + t2)

36(t1 + t2) = 30t1 + 40t2

36t1 + 36t2 = 30t1 + 40t2

6t1 = 4t2

t2 = 1.5 t1

Which means, t2 is greater than t1.

As both Speed and Time of second part is greater than that of first part of the trip, thus,

QUANTITY B IS GREATER
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