Carcass wrote:
A number, x, is randomly selected from the integers from 42 to 92 inclusive.
Quantity A |
Quantity B |
The probability that x is odd. |
The probability that x is even. |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given
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Since even and odd integers alternate, one might incorrectly assume that each probability = 1/2.
However, if there's an odd number of integers in the group (like 4, 5, 6, 7, 8), the number of even integers is
one more than the number of odd integers.
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A nice rule says:
the number of integers from x to y inclusive equals y - x + 1So, the number of integers from 42 to 92 inclusive = 92 - 42 + 1 = 51
Since our integers start and end with an EVEN integer (42 and 92) there must be 26 EVEN integers and 25 ODD integers.
So P(x is EVEN) = 26/51
and P(x is ODD) = 25/51
We get:
QUANTITY A: 25/51
QUANTITY B: 26/51
Answer: B
Cheers,
Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com
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