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A machine can manufacture 20 cans per hour, and exactly 10 s

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A machine can manufacture 20 cans per hour, and exactly 10 s [#permalink] New post 17 Aug 2018, 18:50
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84% (01:23) correct 16% (01:26) wrong based on 25 sessions
A machine can manufacture 20 cans per hour, and exactly 10 such cans fit into every box. Maria packs cans in boxes at a constant rate of 3 boxes per hour. If the machine ran for 2 hours and was then turned off before Maria started packing the cans in boxes, how many minutes would it take Maria to pack all the cans that the machine had made?

(A) 40
(B) 45
(C) 80
(D) 160
(E) 800
[Reveal] Spoiler: OA

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Re: A machine can manufacture 20 cans per hour, and exactly 10 s [#permalink] New post 18 Aug 2018, 00:19
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machine manufactures at the rate of 20 cans per hr
In 2 hr machine m/f 40 cans

3 boxes = 30 cans.
There are total 40 cans to be packed

rate of maria = 30 cans per hr.

For 40 cans total time taken by maria = \(\frac{40}{30}\) hr = 80 mins
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Re: A machine can manufacture 20 cans per hour, and exactly 10 s [#permalink] New post 18 Aug 2018, 12:05
We just have to calculate Maria's rate of packing one box. That's 20 minutes.
So for 4 boxes in 2 hours (40 cans), it'll take 20*4=80.
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Re: A machine can manufacture 20 cans per hour, and exactly 10 s [#permalink] New post 17 Oct 2020, 17:21
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Total cans in 2 hours 20 * 2 = 40

10 can / 1 Box = 40 can / B box
B box = 4 box

Now, 3 box / hour
so, 60 / 3 = M / 4
M = 80
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Re: A machine can manufacture 20 cans per hour, and exactly 10 s [#permalink] New post 20 Oct 2020, 07:42
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Total can manufactured 20 X 2 equal 40
Total box 40/10 equal 4
Time required 1/3 * 4*60 equal 80 min.
Re: A machine can manufacture 20 cans per hour, and exactly 10 s   [#permalink] 20 Oct 2020, 07:42
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