Remember

always this : GRE is a test NOT of calculation but rather to think critically and to find the best and easy way to solve a question.

Now, we said that \(N= 6^A\), which is basically \((2*3)^A\).

In this scenario, our number 876,463 is odd because it ends with 3 and never can be a multiple of \(6^A\) that contains also the 2.

what is the probability that 876,463 is

not a multiple of \(N\)?

Our answer is 100% because we are sure that that number will be never a multiple of \(6^A\).

PS: notice that the first answer is impossible. A probability can never be 0%. It is always between 0 and at most 1.

Hope this helps

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