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A hat contains 18 raffle tickets, numbered 1 through 18. If

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GMAT Club Legend
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A hat contains 18 raffle tickets, numbered 1 through 18. If [#permalink] New post 24 Nov 2017, 20:43
Expert's post
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Question Stats:

87% (01:08) correct 12% (00:32) wrong based on 8 sessions
A hat contains 18 raffle tickets, numbered 1 through 18. If two raffle tickets are chosen at random from the hat, what is the probability that both tickets are even numbers?

A. \(\frac{2}{9}\)
B. \(\frac{4}{17}\)
C. \(\frac{1}{4}\)
D. \(\frac{1}{2}\)
E. \(\frac{33}{34}\)

Drill 1
Question: 8
Page: 522
[Reveal] Spoiler: OA

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Re: A hat contains 18 raffle tickets, numbered 1 through 18. If [#permalink] New post 02 Dec 2017, 10:41
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sandy wrote:
A hat contains 18 raffle tickets, numbered 1 through 18. If two raffle tickets are chosen at random from the hat, what is the probability that both tickets are even numbers?

A. \(\frac{2}{9}\)
B. \(\frac{4}{17}\)
C. \(\frac{1}{4}\)
D. \(\frac{1}{2}\)
E. \(\frac{33}{34}\)

Drill 1
Question: 8
Page: 522


Here
In the number from 1 to 18,
number of even numbers = 9

number of odd numbers = 9

Therefore probability of picking two even numbers = \(\frac{9}{18} * \frac{8}{17}\) = \(\frac{4}{17}\)
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GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4710
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1612 [0], given: 375

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Re: A hat contains 18 raffle tickets, numbered 1 through 18. If [#permalink] New post 10 Dec 2017, 13:17
Expert's post
Explanation

Think of this problem as if you’re pulling out an even ticket and then another even ticket.

So, for the first ticket there are 9 possible evens out of 18 total, so the probability that the first ticket is even is \(\frac{9}{18}\). Now you have one fewer even ticket in the hat. So there are 8 evens out of 17 total tickets for the second ticket, thus, the probability is \(\frac{8}{17}\). You want an even AND aneven, so multiply: \(\frac{9}{18}\times\frac{8}{17}=\frac{4}{17}\).

The answer is choice B.
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Re: A hat contains 18 raffle tickets, numbered 1 through 18. If [#permalink] New post 17 Mar 2018, 23:50
there are 9 even numbers between 1 to 18(inclusive).
total outcomes=18C2
total favourable outcomes=9C2
probability=9C2/18C2 =4/17
Re: A hat contains 18 raffle tickets, numbered 1 through 18. If   [#permalink] 17 Mar 2018, 23:50
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A hat contains 18 raffle tickets, numbered 1 through 18. If

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