Hi Brent,
I am stuck with the approach
Ques:
A fair coin is tossed 5 times. What is the probability of getting at least three heads on consecutive tosses.My take::
Probability of Head or Tails for each coin flip -> (1/2) Multiply by number of coin flips -> (1/2)(1/2)(1/2)(1/2)(1/2) = 1/32
Now we need to find the chance of getting three heads consecutively
So we have 8 scenarios where at LEAST three heads will occur consecutively -> HHHTT, HHHTH, HHHHT, HHHHH, THHHT, THHHH, TTHHH, HTHHH
probability= 8/32 = 1/4
I tried ur approach and got,
P(exactly 3 heads) = 10/32
P(exactly 4 heads) = 5/32
P(exactly 5 heads) = 1/32
Probability = 16/32 = 1/2
am I getting wrong somewhere
Basically you are close, but 1/2 is for both heads and tails. Therefore, the answer should be