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A container holds 4 quarts of alcohol and 4 quarts of water.

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A container holds 4 quarts of alcohol and 4 quarts of water. [#permalink] New post 04 Dec 2017, 04:59
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A container holds 4 quarts of alcohol and 4 quarts of water. How many quarts of water must be added to the container to create a mixture that is 3 parts alcohol to 5 parts water by volume?

A. 4/3
B. 5/3
C. 7/3
D. 8/3
E. 10/3

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Re: A container holds 4 quarts of alcohol and 4 quarts of water. [#permalink] New post 04 Dec 2017, 14:09
Bunuel wrote:
A container holds 4 quarts of alcohol and 4 quarts of water. How many quarts of water must be added to the container to create a mixture that is 3 parts alcohol to 5 parts water by volume?

A. 4/3
B. 5/3
C. 7/3
D. 8/3
E. 10/3



Here
\(\frac{4 quarts of Alcohol}{4 quarts of water}\)

we need to add water to above solution to make it equal to = \(\frac{3 parts of Alcohol}{5 parts of water}\)
Let w= quarts of water required

Total quarts of water = (4 + w)

Therefore we can re write as -

\(\frac{4 quarts of Alcohol}{(4 quarts of water + w)}\) = \(\frac{3 parts of Alcohol}{5 parts of water}\)(since we need to add w to make the ratio equal to 3/5)

or \(\frac{4}{(4+w)}\) =\(\frac{3}{5}\)

or w =\(\frac{8}{3}\)
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Re: A container holds 4 quarts of alcohol and 4 quarts of water. [#permalink] New post 05 Jan 2018, 07:46
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Bunuel wrote:
A container holds 4 quarts of alcohol and 4 quarts of water. How many quarts of water must be added to the container to create a mixture that is 3 parts alcohol to 5 parts water by volume?

A. 4/3
B. 5/3
C. 7/3
D. 8/3
E. 10/3


We can create the following equation in which n = the added water:

4/(4 + n) = 3/5

20 = 12 + 3n

8 = 3n

8/3 = n

Answer: D
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GRE Quant Self-Study Course
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Re: A container holds 4 quarts of alcohol and 4 quarts of water.   [#permalink] 05 Jan 2018, 07:46
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A container holds 4 quarts of alcohol and 4 quarts of water.

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