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# A child has 6 magnetic letters: C, H, I, I, P, and P. How ma

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A child has 6 magnetic letters: C, H, I, I, P, and P. How ma [#permalink]  21 Nov 2018, 00:14
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A child has 6 magnetic letters: C, H, I, I, P, and P. How many different "words" can the child spell using all these letters?

A. 720

B. 360

C. 180

D. 90

E. 45
[Reveal] Spoiler: OA

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Re: A child has 6 magnetic letters: C, H, I, I, P, and P. How ma [#permalink]  23 Nov 2018, 13:46
Carcass wrote:
A child has 6 magnetic letters: C, H, I, I, P, and P. How many different "words" can the child spell using all these letters?

A. 720

B. 360

C. 180

D. 90

E. 45

Because we have two identical letters I and P it means we have to reduce that option.

If they were 6 different letters it would be 6! = 720

But given that we have 2 P and 2 I

We have to divide by 2! * 2!

6!/(2! * 2!) = 720/(2*2) = 360/2 = 180

Re: A child has 6 magnetic letters: C, H, I, I, P, and P. How ma   [#permalink] 23 Nov 2018, 13:46
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