Re: A certain train is traveling at a constant rate. If the trai
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04 Nov 2020, 08:28
In case the above post isn't clear enough here it is broken down:
First I changed the S & T because it's confusing when using speed equations where usually S = speed (probably could keep T for Time, but I digress)
Speed equations:
Speed = \(\frac{distance}{time} \) Time= \(\frac{distance}{speed}\) Distance = \(\frac{speed}{time}\)
Changed variables: S--> M (miles) T--> H (hours) D2 --> Y
Speed = M/H
Problem: If the train travels "M" miles in "H" hours, in how many hours will the train travel Y(D2) miles?
Find H:
Time= \(\frac{distance}{speed} \)
(Plug variables)
Distance = Y
Speed = \(\frac{distance}{time}\) ---> \(\frac{M}{H
}\)
Time --> Y/(\(\frac{M}{H}\)
Remember, DIVISION of a fraction = multiplication of reciprocal
So:
Y/(\(\frac{M}{H}\)) = \(\frac{Y}{1}\) * \(\frac{H}{M}\) = \(\frac{YH}{M}\)
Replace the variables:
\(\frac{YH}{M}\) = \(\frac{YT}{S}\)
Option C
Tah dahhh