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A certain pet store sells only dogs and cats. In March, the

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A certain pet store sells only dogs and cats. In March, the [#permalink] New post 24 May 2017, 01:44
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A certain pet store sells only dogs and cats. In March, the store sold twice as many dogs as cats. In April, the store sold twice the number of dogs that it sold in March, and three times the number of cats that it sold in March. If the total number of pets the store sold in March and April combined was 500, how many dogs
did the store sell in March?

A) 80

B) 100

C) 120

D) 160

E) 180
[Reveal] Spoiler: OA

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Re: A certain pet store sells only dogs and cats. In March, the [#permalink] New post 10 Oct 2017, 09:03
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So, in March the store has sold twice as dogs as cats, i.e. D = 2C and C cats.

In April, the store has sold double the dogs of March, i.e. 2D = 4C and triple of cats as in March, 3C.

Now we know that the sum of all sold animals is 500 = 2C + C + 4C + 3C = 10C. Thus, C = 50 and thus the number of dogs sold in March is equal to 2C = 2*50 = 100. Answer B
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Re: A certain pet store sells only dogs and cats. In March, the [#permalink] New post 28 May 2018, 18:25
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A certain pet store sells only dogs and cats. In March, the store sold twice as many dogs as cats. In April, the store sold twice the number of dogs that it sold in March, and three times the number of cats that it sold in March. If the total number of pets the store sold in March and April combined was 500, how many dogs
did the store sell in March?

A) 80

B) 100

C) 120

D) 160

E) 180


We can let the number of cats sold in March = c and the number of dogs sold in March = 2c

Thus the number of dogs sold in April = 4c and the number of cats sold in April = 3c.

We can now create the equation:

c + 2c + 4c + 3c = 500

10c = 500

c = 50

Thus, 2c = 100 dogs were sold in March.

Answer: B
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Re: A certain pet store sells only dogs and cats. In March, the   [#permalink] 28 May 2018, 18:25
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