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A certain jar contains 60 jelly beans—22 white, 18 green, 11

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A certain jar contains 60 jelly beans—22 white, 18 green, 11 [#permalink] New post 10 Sep 2017, 11:57
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Question Stats:

86% (00:45) correct 13% (01:29) wrong based on 53 sessions
A certain jar contains 60 jelly beans—22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a jelly bean is to be chosen at random, what is the probability that the jelly bean will be neither red nor purple?

A. 0.09

B. 0.15

C. 0.54

D. 0.85

E. 0.91

Practice Questions
Question: 5
Page: 120
Difficulty: medium
[Reveal] Spoiler: OA

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Re: A certain jar contains 60 jelly beans—22 white, 18 green, 11 [#permalink] New post 10 Sep 2017, 12:01
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Explanation

Since there are 5 red and 4 purple jelly beans in the jar, there are 51 that are neither red nor purple, and the probability of selecting one of these is \(\frac{51}{60}\).Since all of the answer choices are decimals, you must convert the fraction to its decimal equivalent, 0.85
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Re: A certain jar contains 60 jelly beans—22 white, 18 green, 11 [#permalink] New post 21 Jun 2019, 08:24
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Carcass wrote:
A certain jar contains 60 jelly beans—22 white, 18 green, 11 yellow, 5 red, and 4 purple. If a jelly bean is to be chosen at random, what is the probability that the jelly bean will be neither red nor purple?

A. 0.09

B. 0.15

C. 0.54

D. 0.85

E. 0.91

Practice Questions
Question: 5
Page: 120
Difficulty: medium


Since the only colors are white, green, yellow, red, and purple, we can see that NOT getting red or purple is the same as GETTING white, green or yellow

So, P(NOT getting red or purple) = P(GETTING white, green or yellow)

There are 60 jellybeans in total.
Number of jellybeans that are white, green or yellow = 22 + 18 + 11 = 51

So, P(GETTING white, green or yellow) = 51/60
= 17/20
= 0.85

Answer: D

Cheers,
Brent
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Re: A certain jar contains 60 jelly beans—22 white, 18 green, 11   [#permalink] 21 Jun 2019, 08:24
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