Explanation

Now here we have 5 places to fill S1, S2, D1, D2 and D3 respectively.

Repetition is allowedS1: can take vale of 26 alphabets (26 options)

S2: can take vale of 26 alphabets (26 options)

D1: can take vale of 10 digits (10 options)

D2: can take vale of 10 digits (10 options)

D3: can take vale of 10 digits (10 options)

Total no of possibilities = \(S1 \times S2 \times D1 \times D2 \times D3\)= \(26 \times 26 \times 10 \times 10 \times 10\) = 676,000.

Hence B is the correct option.
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Sandy

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