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A certain collector

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A certain collector [#permalink] New post 15 May 2018, 07:27
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Question Stats:

60% (02:50) correct 40% (03:03) wrong based on 5 sessions
A certain collector sold \(\frac{5}{8}\) of her paintings, including \(\frac{2}{3}\) of her impressionist paintings. If \(\frac{3}{5}\) of her paintings were impressionist, what fraction of the paintings that were NOT SOLD were impressionist?

A. \(\frac{1}{4}\)

B. \(\frac{3}{8}\)

C. \(\frac{2}{5}\)

D. \(\frac{8}{15}\)

E. \(\frac{5}{8}\)
[Reveal] Spoiler: OA

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Re: A certain collector [#permalink] New post 03 Aug 2018, 22:18
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Carcass wrote:
A certain collector sold \(\frac{5}{8}\) of her paintings, including \(\frac{2}{3}\) of her impressionist paintings. If \(\frac{3}{5}\) of her paintings were impressionist, what fraction of the paintings that were NOT SOLD were impressionist?

A. \(\frac{1}{4}\)

B. \(\frac{3}{8}\)

C. \(\frac{2}{5}\)

D. \(\frac{8}{15}\)

E. \(\frac{5}{8}\)



For easy calculation let's take the total no. of painting = 120

Now Total painting sold = \(\frac{5}{8} * 120 = 75\)

Therefore number of paintings not sold = \(120 - 75 = 45\)

Total number of impressionist painting = \(\frac{3}{5} * 120 = 72\)

Number of impressionist paintings sold = \(\frac{2}{3}* 72 = 48\)

Therefore number of impressionist paintings not sold = \(72 - 48 = 24\)

Therefore, the fraction of paintings that were not sold were impressionist = \(\frac{24}{45} = \frac{8}{15}\)
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Re: A certain collector   [#permalink] 03 Aug 2018, 22:18
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A certain collector

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