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A brown flask contains a concoction that is 20% alcohol.

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A brown flask contains a concoction that is 20% alcohol. [#permalink] New post 26 Jun 2020, 00:55
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A brown flask contains a concoction that is 20% alcohol. A red flask contains a concoction with an unknown amount of alcohol. An equal amount of both flasks is poured into an empty jug. If the resulting mixture has an alcohol concentration that is 30% greater than the alcohol concentration of the brown flask, what percent alcohol did the red flask originally contain?

(A) 23%

(B) 25%

(C) 32%

(D) 33%

(E) 40%
[Reveal] Spoiler: OA

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Re: A brown flask contains a concoction that is 20% alcohol. [#permalink] New post 26 Jun 2020, 06:22
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The brown flask contains 20% alcohol, the final mixture has an alcohol content thats 30% greater than the brown flask concentration.
20 * 1.30 = 26% - final alcohol concentration (30% greater than starting 20%)

Now basically if we combine 2 alcoholic mixtures in the equal amounts the resulting mixture will have the alcohol content of the average between the two percentages. (ex. if the two jugs have 20% and 22%, the combined mixture will be 21%)

To get 26% final concentration we must then have 32% alcohol in the red flask ([20+32]/2 = 26%)
So the answer is C
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Re: A brown flask contains a concoction that is 20% alcohol.   [#permalink] 26 Jun 2020, 06:22
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A brown flask contains a concoction that is 20% alcohol.

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