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A bookcase has s shelves with n books on each shelf, where

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A bookcase has s shelves with n books on each shelf, where [#permalink] New post 07 Dec 2017, 03:24
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A bookcase has s shelves with n books on each shelf, where n is a multiple of both s and s-1. If all of the books on the highest shelf were removed and redistributed equally among the other shelves, which of the following represents the number of books that would be on each of the other shelves?

A. \frac{ns}{s - 1}

B. \frac{n(s+1)}{s}

C. \frac{(n+1)s}{s-1}

D. \frac{(n-1)s}{s-1}

E. \frac{(n+1)(s-1)}{s}
[Reveal] Spoiler: OA

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Re: A bookcase has s shelves with n books on each shelf, where [#permalink] New post 07 Dec 2017, 15:03
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Hello,

in my opinion the answer should be A.

Basically the number of total books does not change. This will still be s*n, however the number of shelves has decreased by 1, which gives us S-1.

Distributing the total number of books on the remaining shelves therefore gives us:

(sn)/(s-1)
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Re: A bookcase has s shelves with n books on each shelf, where [#permalink] New post 08 Dec 2017, 04:03
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Added the OA

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Re: A bookcase has s shelves with n books on each shelf, where   [#permalink] 08 Dec 2017, 04:03
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