This problem can be solved algebraically.

The length of the board = L

It is cut into two pieces, one smaller and another larger.

Lets call the smaller piece S.

Now we know that the length of the longer piece is 2.S + 1.

But the choices are all representing the length of the longer piece in terms of L, the total length of the board.

So we need an equation relating S to L so that 2.S + 1 can be represented in terms of L, the total length, instead of the smaller piece S.

Since Length of the board = Length of the Smaller Piece + Length of the Larger Piece

L = S + 2.S + 1

L = 3.S + 1

3.S + 1 = L

3.S = L - 1

S = (L - 1)/3

Now we substitute the above equation into 2.S + 1, which is the length of the longer piece in terms of the shorter piece.

=> 2.[(L - 1)/3] + 1

= 2.[(L-1) + 3]/3

= (2.L - 2 + 3)/3

= (2.L + 1)/3

Answer is E.

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos

GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests