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# A bag contains 6 red chips numbered 1 through 6, respectivel

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Joined: 07 Jun 2014
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GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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A bag contains 6 red chips numbered 1 through 6, respectivel [#permalink]  05 Aug 2018, 14:28
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Question Stats:

50% (00:59) correct 50% (00:40) wrong based on 4 sessions
A bag contains 6 red chips numbered 1 through 6, respectively, and 6 blue chips numbered 1 through 6, respectively. If 2 chips are to be picked sequentially from the bag of 12 chips, without replacement, what is the probability of picking a red chip and then a blue chip with the same number?

[Reveal] Spoiler: OA
$$\frac{1}{22}$$

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Sandy
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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1783 [0], given: 397

Re: A bag contains 6 red chips numbered 1 through 6, respectivel [#permalink]  07 Aug 2018, 16:46
Expert's post
Explanation

The trap answer in this problem is $$\frac{1}{6}\times \frac{1}{6}$$.

This is not the answer to the question being asked—rather, this is the answer to the question, “What is the probability of picking a red chip and then a blue chip that both have #3?” (or any other specific number). This is a more specific question than the one actually asked. In the question, asked, there are six possible ways to fulfill the requirements of the problem, not one, because the problem does not specify whether the number should be 1, 2, 3, 4, 5, or 6.

Thus, any of the 6 red chips is acceptable for the first pick. However, on the second pick, only the blue chip with the same number as the red one that was just picked is acceptable (the chip must “match” the first one picked). Thus:

$$\frac{6}{12}\times \frac{1}{11}=\frac{1}{22}$$.
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Sandy
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Re: A bag contains 6 red chips numbered 1 through 6, respectivel   [#permalink] 07 Aug 2018, 16:46
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