STRATEGY: Notice that e is the median of the 11 values, and Quantity B represents the mean of the 11 values. This should remind us of the following property:

Key Property: "In a set where the numbers are equally spaced, the mean will equal the median."
For example, in each of the following sets, the mean and median are equal:
{7, 9, 11, 13, 15}
{-1, 4, 9, 14}
{3, 4, 5, 6}

So, if the 11 variables (from a to k) are consecutive integers, then median = mean = e = Quantity B, in which case the two quantities are equal

Conversely, if k = 1, j = 2, i = 3......, c = 9, b = 10, and a = 1,000,000,000, then Quantity B (the mean of the 11 values) is greater than Quantity A (the median of the 11 values)

Answer: D
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We are given with the set of numbers in the descending order. But the values are not known. Hence, their average could either be greater than, less than, or equal to e.

For better and a quick understanding, let's consider a small set 10 > 9 >8 > x > 4 >3 > 2. If x is 7, the average will be 6.14. If x= 5, the average will be 5.85. Hence, the answer is D.
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major L....e is not the median. F is....nice try bro better luck next time