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a, b, c, d, and e are five consecutive numbers in increasin

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a, b, c, d, and e are five consecutive numbers in increasin [#permalink] New post 30 May 2018, 01:42
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a, b, c, d, and e are five consecutive numbers in increasing order of size. Deleting one of the five numbers from the set decreased the sum of the remaining numbers in the set by 20%. Which one of the following numbers was deleted?

(A) a

(B) b

(C) c

(D) d

(E) e
[Reveal] Spoiler: OA

Last edited by Carcass on 30 May 2018, 15:48, edited 1 time in total.
Edited by Carcass
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Re: a, b, c, d, and e are five consecutive numbers in increasin [#permalink] New post 31 May 2018, 06:41
Expert's post
The numbers in the set \({a,b,c,d,e}\).

Rewriting the numbers as \({n-2,n-1,n,n+1,n+2}\) since they are consecutive.

Sum \(= n-2 + n-1 + n + n+1 + n+2 = 5n\)

For 20 percent reduction you need to remove n. Hence the number n is removed from the set.

Hence option C is correct
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Re: a, b, c, d, and e are five consecutive numbers in increasin   [#permalink] 31 May 2018, 06:41
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a, b, c, d, and e are five consecutive numbers in increasin

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