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Retired Moderator Joined: 07 Jun 2014
Posts: 4808
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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Kudos [?]: 2282 , given: 393

a, b, c, and d are consecutive integers such that a < b < c [#permalink]
Expert's post 00:00

Question Stats: 74% (00:32) correct 25% (00:43) wrong based on 35 sessions
a, b, c, and d are consecutive integers such that $$a < b < c < d$$.

 Quantity A Quantity B The average (arithmetic mean) of a, b, c, and d The average (arithmetic mean)of b and c

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________

Sandy
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Try our free Online GRE Test Active Member Joined: 29 May 2018
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Kudos [?]: 98  , given: 4

Re: a, b, c, and d are consecutive integers such that a < b < c [#permalink]
1
KUDOS
sandy wrote:
a, b, c, and d are consecutive integers such that $$a < b < c < d$$.

 Quantity A Quantity B The average (arithmetic mean) of a, b, c, and d The average (arithmetic mean)of b and c

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Let the series be 4<3<2<1 as consecutive integers.

avg of four number = 10/4 = 2.5

b+c avg = b+c/2 = 5/2 = 2.5.

both same . C. GRE Instructor Joined: 10 Apr 2015
Posts: 2569
Followers: 91

Kudos [?]: 2736  , given: 40

Re: a, b, c, and d are consecutive integers such that a < b < c [#permalink]
1
KUDOS
Expert's post
sandy wrote:
a, b, c, and d are consecutive integers such that $$a < b < c < d$$.

 Quantity A Quantity B The average (arithmetic mean) of a, b, c, and d The average (arithmetic mean)of b and c

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Here's an algebraic approach:

If a, b, c, and d are consecutive integers such that $$a < b < c < d$$, then we can conclude the following:
$$a = a$$ (no duh )
$$b = a + 1$$
$$c = a + 2$$
$$d = a + 3$$

We can now replace b, c and d with their equivalent values to get:

Quantity A: Average $$= \frac{a+(a+1)+(a+2)+(a+3)}{4}= \frac{4a+6}{4}=\frac{4a}{4}+\frac{6}{4}=a+1.5$$

Quantity B: Average $$=\frac{(a+1)+(a+2)}{2}=\frac{2a+3}{2}=\frac{2a}{2}+\frac{3}{2}=a+1.5$$

Cheers,
Brent

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Brent Hanneson – Creator of greenlighttestprep.com Re: a, b, c, and d are consecutive integers such that a < b < c   [#permalink] 20 Aug 2019, 10:33
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