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GRE Math Challenge #8- a, b and c are multiple of 15 [#permalink]
05 Aug 2014, 03:42

Expert's post

00:00

Question Stats:

64% (00:59) correct
35% (01:14) wrong based on 105 sessions

a, b and c are multiples of 15, and 0 < a < b < c

Quantity A

Quantity B

The remainder when b is divided by c

The remainder when (b + c) is divided by a

A) The quantity in Column A is greater. B) The quantity in Column B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.

Re: GRE Math Challenge #8- a, b and c are multiple of 15 [#permalink]
19 Sep 2016, 10:41

I think the answer is D. I took 15,30 and 45 at first and here A is greater. But then I took 15, 30 and 150 30/150 leaves a quotient of 0.2 and a remainder of 0. Hence D

Re: GRE Math Challenge #8- a, b and c are multiple of 15 [#permalink]
21 Sep 2016, 04:57

3

This post received KUDOS

Expert's post

Given: a < b < c

Quantity A: The remainder when b is divided by c Notice that c is greater than b So, b divided by c will equal 0 with remainder b If this isn't 100% clear, here are a few examples. 4 divided by 6 equals 0 with remainder 4. Likewise, 2 divided by 7 equals 0 with remainder 2. So, we get..... Quantity A: b

Quantity B: The remainder when (b + c) is divided by a IMPORTANT CONCEPT When positive integer N is divided by positive integer D, the remainder R is such that 0 < R < D For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0 So, we can conclude that.... Quantity B: some integer that's less than a

Since it's given that a < b, we can be certain that quantity A is greater.

a, b, and c are multiples of 15 and a < b < c [#permalink]
29 Oct 2016, 04:40

Expert's post

a, b, and c are multiples of 15 and a < b < c

Quantity A

Quantity B

The remainder when b is divided by c

The remainder when (b + c) is divided by a

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Drill 2 Question: 2 Page: 290

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Sandy If you found this post useful, please let me know by pressing the Kudos Button

Re: a, b, and c are multiples of 15 and a < b < c [#permalink]
29 Oct 2016, 04:43

Expert's post

Explanation

Try Plugging In. If a = 15, b = 30, and c = 60, Quantity A is 30 because c cannot divide into b even one time. Quantity B is 0 because 90 divided by 15 has no remainder. Eliminate choices (B) and (C).

Try a new set of numbers to further narrow your choices. If a = 30, b = 45, and c = 120, Quantity A is 45, and Quantity B is 15. The answer is choice A.
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Sandy If you found this post useful, please let me know by pressing the Kudos Button

Re: GRE Math Challenge #8- a, b and c are multiple of 15 [#permalink]
19 Dec 2016, 01:17

i think the answer will be D, when I take 15, 30, 45 then for the A quantity remainder will be 15, and for B is 0, then A is BIG, but if I take 15, 30, 150 ( i can take this, cause You didnt tell me that it will be consecutive multiples) then the remainder will be 0 for the quantity A and B, then the answer ll be D! Can you explain it?

Re: a, b, and c are multiples of 15 and a < b < c [#permalink]
26 Mar 2018, 02:20

1

This post received KUDOS

sandy wrote:

Explanation

Try Plugging In. If a = 15, b = 30, and c = 60, Quantity A is 30 because c cannot divide into b even one time. Quantity B is 0 because 90 divided by 15 has no remainder. Eliminate choices (B) and (C).

Try a new set of numbers to further narrow your choices. If a = 30, b = 45, and c = 120, Quantity A is 45, and Quantity B is 15. The answer is choice A.

When it comes to this question, don't we need to consider negative numbers?

Re: a, b, and c are multiples of 15 and a < b < c [#permalink]
27 Aug 2018, 07:45

when dealing with these types of questions we usually consider negative numbers as well. So why we are not considering negative numbers in this question?

Re: a, b, and c are multiples of 15 and a < b < c [#permalink]
27 Aug 2018, 10:16

3

This post received KUDOS

Expert's post

sandy wrote:

a, b, and c are multiples of 15 and a < b < c

Quantity A

Quantity B

The remainder when b is divided by c

The remainder when (b + c) is divided by a

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Drill 2 Question: 2 Page: 290

Remainder rule: When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < D For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0

QUANTITY A: The remainder when b is divided by c Since c is greater than b, we know that: b divided by c equals zero with remainder b For example, 30 divided by 75 equals 0 with remainder 30 So, QUANTITY A = b

QUANTITY B: The remainder when (b + c) is divided by a According to the above rule, the remainder must be LESS THAN a So, QUANTITY B = some number less than a

We have: QUANTITY A: b QUANTITY B: some number less than a Since we are told that a < b < c, we can see that Quantity A is greater.

Answer: A

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Re: GRE Math Challenge #8- a, b and c are multiple of 15 [#permalink]
16 Oct 2019, 06:53

1

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Expert's post

IlCreatore wrote:

This is right instead. 0 divided by any number is 0 with remainder of zero and the definition of multiple does not forbid to look for negative multiples, unless stated we are using positive multiples. So the Answer should be D.

Does anybody have the OA/OE?

Good point. The question does not state that a, b and c are POSITIVE multiples. I never noticed that the first time I read the question.

When it comes to remainder/divisibility questions on the GRE, there will always be some proviso that states the values are positive integers. In my opinion, it's a bad question.

I'm going to edit the question so that it has the required provisos.

Cheers, Brent
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