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a, b, and c are multiples of 15 and a < b < c

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a, b, and c are multiples of 15 and a < b < c [#permalink] New post 29 Oct 2016, 04:40
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Question Stats:

68% (01:09) correct 32% (00:42) wrong based on 25 sessions
a, b, and c are multiples of 15 and a < b < c

Quantity A
Quantity B
The remainder when b is divided by c
The remainder when (b + c) is divided by a


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Drill 2
Question: 2
Page: 290
[Reveal] Spoiler: OA

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Joined: 07 Jun 2014
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Re: a, b, and c are multiples of 15 and a < b < c [#permalink] New post 29 Oct 2016, 04:43
Expert's post
Explanation

Try Plugging In. If a = 15, b = 30, and c = 60, Quantity A is 30 because c cannot divide into b even one time. Quantity B is 0 because 90 divided by 15 has no remainder. Eliminate choices (B) and (C).

Try a new set of numbers to further narrow your choices. If a = 30, b = 45, and c = 120, Quantity A is 45, and Quantity B is 15. The answer is choice A.
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Re: a, b, and c are multiples of 15 and a < b < c [#permalink] New post 26 Mar 2018, 02:20
sandy wrote:
Explanation

Try Plugging In. If a = 15, b = 30, and c = 60, Quantity A is 30 because c cannot divide into b even one time. Quantity B is 0 because 90 divided by 15 has no remainder. Eliminate choices (B) and (C).

Try a new set of numbers to further narrow your choices. If a = 30, b = 45, and c = 120, Quantity A is 45, and Quantity B is 15. The answer is choice A.



When it comes to this question, don't we need to consider negative numbers?

If we do, what the result will be?
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Re: a, b, and c are multiples of 15 and a < b < c [#permalink] New post 26 Mar 2018, 08:05
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This is a good question..

All the questions I have encountered have positive numbers when asking for remainder.

Remainder is a positive number. So Say \(-11 \div 5\) has a remainder of 4 not -1.

Let me look around and get back to you on this one.
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Re: a, b, and c are multiples of 15 and a < b < c [#permalink] New post 27 Aug 2018, 07:45
when dealing with these types of questions we usually consider negative numbers as well. So why we are not considering negative numbers in this question?
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Re: a, b, and c are multiples of 15 and a < b < c [#permalink] New post 27 Aug 2018, 10:16
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sandy wrote:
a, b, and c are multiples of 15 and a < b < c

Quantity A
Quantity B
The remainder when b is divided by c
The remainder when (b + c) is divided by a


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Drill 2
Question: 2
Page: 290


Remainder rule:
When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < D
For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0

QUANTITY A: The remainder when b is divided by c
Since c is greater than b, we know that: b divided by c equals zero with remainder b
For example, 30 divided by 75 equals 0 with remainder 30
So, QUANTITY A = b

QUANTITY B: The remainder when (b + c) is divided by a
According to the above rule, the remainder must be LESS THAN a
So, QUANTITY B = some number less than a

We have:
QUANTITY A: b
QUANTITY B: some number less than a
Since we are told that a < b < c, we can see that Quantity A is greater.

Answer: A

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Re: a, b, and c are multiples of 15 and a < b < c   [#permalink] 27 Aug 2018, 10:16
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