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a ≠ b

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a ≠ b [#permalink] New post 23 Jun 2018, 12:28
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Question Stats:

61% (00:36) correct 38% (00:35) wrong based on 89 sessions
\(a \neq b\)

Quantity A
Quantity B
\(\frac{a-b}{b-a}\)
1


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: a ≠ b [#permalink] New post 26 Jun 2018, 07:51
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sandy wrote:
\(a \neq b\)

Quantity A
Quantity B
\(\frac{a-b}{b-a}\)
1


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



From the statement; statement B > Statement 1

If we put any values in Statement 1 it will always result = -1 which is less than statement 2
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Re: a ≠ b [#permalink] New post 27 Jun 2018, 17:01
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(a-b)/(b-a)=(a-b)/-(a-b)=-1<1 -> B
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Re: a ≠ b [#permalink] New post 18 Jul 2018, 07:38
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Explanation

Plug in any two unequal values for a and b, and Quantity A will always be equal to –1. This is because a negative sign can be factored out of the top or bottom of the fraction to show that the top and bottom are the same, except for their signs:

\(\frac{a-b}{b-b}=\frac{a-b}{-(a-b)}=-1\)
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Re: a ≠ b [#permalink] New post 10 Apr 2019, 06:20
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@ScottTargetTestPrep @Sandy

A quick help, please!

I was trying a different approach, but I does not work, why?

I did the following:


Quant A
a-b/b-a

Quant B
1 is the same as b-a/b-a

so, I need to compare a-b (Quant A) with b-a (Quant B)

Just I pick some numbers, but the answer is D:

Option 1: a=2, b=-3


QA: a-b = -1
QB: b-a = -3-2 = -5
so QA>QB

Option 1: a=-2, b=3

QA: a-b = 1
QB: b-a = 3+2 =5
so QB>QA

Why?
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Re: a ≠ b [#permalink] New post 10 Apr 2019, 06:40
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dcmartinezp wrote:
@ScottTargetTestPrep @Sandy

A quick help, please!

I was trying a different approach, but I does not work, why?

I did the following:


Quant A
a-b/b-a

Quant B
1 is the same as b-a/b-a

so, I need to compare a-b (Quant A) with b-a (Quant B)

Just I pick some numbers, but the answer is D:

Option 1: a=2, b=-3


QA: a-b = -1
QB: b-a = -3-2 = -5
so QA>QB

Option 1: a=-2, b=3

QA: a-b = 1
QB: b-a = 3+2 =5
so QB>QA

Why?


You got here:
QUANTITY A: (a-b)/(b-a)
QUANTITY B: (b-a)/(b-a)

From here, you basically multiplied both quantities by (b-a) to get:
QUANTITY A: (a-b)
QUANTITY B: (b-a)


This is where the problem lies.
We don't know whether (b-a) is POSITIVE or NEGATIVE.

As such, we cannot multiply both quantities by (b-a)

For more on this, watch the following:

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Re: a ≠ b [#permalink] New post 10 Apr 2019, 07:00
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Hi @GreenlightTestPrep Brent, thank you by your message!

It's a little confuse for me that I have just the option provided by Sandy/MGRE. Just I imagine myself doing the test and no be sure that I could use picking numbers or another strategy..


How do you do this exercise using picking numbers without a err as I had?
I tried two options, just because I was conscious that I do not know whether the values of a and b are positive or negative, integers of fractions.


Thank you
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Re: a ≠ b [#permalink] New post 10 Apr 2019, 09:22
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dcmartinezp wrote:
Hi @GreenlightTestPrep Brent, thank you by your message!

It's a little confuse for me that I have just the option provided by Sandy/MGRE. Just I imagine myself doing the test and no be sure that I could use picking numbers or another strategy..


How do you do this exercise using picking numbers without a err as I had?
I tried two options, just because I was conscious that I do not know whether the values of a and b are positive or negative, integers of fractions.


Thank you

It's totally fine to test values. HOWEVER, you cannot first simplify the quantities as you did the first time.

We start with:
QUANTITY A: (a-b)/(b-a)
QUANTITY B: 1

Case 1
If a = 2, and b = -3, we get:
QUANTITY A: (2 - -3)/(-3 - 2) = 5/-5 = -1
QUANTITY B: 1
Quantity B is greater


Case 2
If a = -2, and b = 3, we get:
QUANTITY A: (-2 - 3)/(3 - -2) = -5/5 = -1
QUANTITY B: 1
Quantity B is greater


Case 3
If a = 1, and b = 7, we get:
QUANTITY A: (1 - 7)/(7 - 1) = -7/7 = -1
QUANTITY B: 1
Quantity B is greater


Case 4
If a = 11, and b = 2, we get:
QUANTITY A: (11 - 2)/(2 - 11) = 9/-9 = -1
QUANTITY B: 1
Quantity B is greater

Etc...

Does that help?

Cheers,
Brent
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Re: a ≠ b [#permalink] New post 08 May 2020, 03:51
Why not just factor a -1 out of the denominator or numerator to get -1 * 1? Worked for me and super fast!
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Re: a ≠ b [#permalink] New post 09 May 2020, 04:05
Didnt understand the condition a negative or b negative
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Re: a ≠ b [#permalink] New post 09 May 2020, 05:50
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NickBass wrote:
Why not just factor a -1 out of the denominator or numerator to get -1 * 1? Worked for me and super fast!


Exactly.
That's how @leanhdung and @sandy (above) answered the question.
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Re: a ≠ b [#permalink] New post 09 May 2020, 05:52
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Nikhil4GRE wrote:
Didnt understand the condition a negative or b negative


I'm not too sure what you're asking. Can you elaborate?
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Re: a ≠ b   [#permalink] 09 May 2020, 05:52
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