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62% (00:34) correct
37% (00:34) wrong based on 95 sessions

\(a \neq b\)

Quantity A

Quantity B

\(\frac{a-b}{b-a}\)

1

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

From the statement; statement B > Statement 1

If we put any values in Statement 1 it will always result = -1 which is less than statement 2
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Plug in any two unequal values for a and b, and Quantity A will always be equal to –1. This is because a negative sign can be factored out of the top or bottom of the fraction to show that the top and bottom are the same, except for their signs:

Hi @GreenlightTestPrep Brent, thank you by your message!

It's a little confuse for me that I have just the option provided by Sandy/MGRE. Just I imagine myself doing the test and no be sure that I could use picking numbers or another strategy..

How do you do this exercise using picking numbers without a err as I had? I tried two options, just because I was conscious that I do not know whether the values of a and b are positive or negative, integers of fractions.

Thank you
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Diana

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Hi @GreenlightTestPrep Brent, thank you by your message!

It's a little confuse for me that I have just the option provided by Sandy/MGRE. Just I imagine myself doing the test and no be sure that I could use picking numbers or another strategy..

How do you do this exercise using picking numbers without a err as I had? I tried two options, just because I was conscious that I do not know whether the values of a and b are positive or negative, integers of fractions.

Thank you

It's totally fine to test values. HOWEVER, you cannot first simplify the quantities as you did the first time.

We start with: QUANTITY A: (a-b)/(b-a) QUANTITY B: 1

Case 1 If a = 2, and b = -3, we get: QUANTITY A: (2 - -3)/(-3 - 2) = 5/-5 = -1 QUANTITY B: 1 Quantity B is greater

Case 2 If a = -2, and b = 3, we get: QUANTITY A: (-2 - 3)/(3 - -2) = -5/5 = -1 QUANTITY B: 1 Quantity B is greater

Case 3 If a = 1, and b = 7, we get: QUANTITY A: (1 - 7)/(7 - 1) = -7/7 = -1 QUANTITY B: 1 Quantity B is greater

Case 4 If a = 11, and b = 2, we get: QUANTITY A: (11 - 2)/(2 - 11) = 9/-9 = -1 QUANTITY B: 1 Quantity B is greater

Etc...

Does that help?

Cheers, Brent
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Brent Hanneson – Creator of greenlighttestprep.com Sign up for GRE Question of the Dayemails