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a + b/10>0

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a + b/10>0 [#permalink] New post 15 Apr 2018, 10:05
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Question Stats:

73% (01:02) correct 26% (00:55) wrong based on 53 sessions


\(a + \frac{b}{10} > 0\)

\(b + \frac{a}{10} < 0\)

Quantity A
Quantity B
a
b


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
[Reveal] Spoiler: OA

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Re: a + b/10>0 [#permalink] New post 09 Jul 2018, 18:42
Carcass wrote:
\(a + \frac{b}{10} > 0\)

\(b + \frac{a}{10} < 0\)

Quantity A
Quantity B
a
b


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

My Anwer is A
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Re: a + b/10>0 [#permalink] New post 20 Aug 2019, 12:30
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Expert's post
Carcass wrote:


\(a + \frac{b}{10} > 0\)

\(b + \frac{a}{10} < 0\)

Quantity A
Quantity B
a
b


A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


Take: \(a + \frac{b}{10} > 0\)
Multiply both sides by 10 to get: \(10a + b > 0\)

Take: \(b + \frac{a}{10} < 0\)
Multiply both sides by 10 to get: \(10b + a < 0\)
Multiply both sides by -1 to get: \(-10b - a > 0\) [since I multiplied both sides by a NEGATIVE value, I had to REVERSE the direction of the inequality symbol]
Rearrange to get: \(-a - 10b > 0\)

We now have:
\(10a + b > 0\)
\(-a - 10b > 0\)

Since the inequality symbols are facing the SAME DIRECTION, we can ADD the inequalities to get: \(9a - 9b > 0\)
Divide both sides by 9 to get: \(a - b > 0\)
Add b to both sides to get: \(a > b\)

Answer: A

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Re: a + b/10>0 [#permalink] New post 25 Aug 2019, 06:55
A
Re: a + b/10>0   [#permalink] 25 Aug 2019, 06:55
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