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a + b/10>0

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a + b/10>0 [#permalink]  15 Apr 2018, 10:05
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Question Stats:

73% (01:02) correct 26% (00:55) wrong based on 53 sessions

$$a + \frac{b}{10} > 0$$

$$b + \frac{a}{10} < 0$$

 Quantity A Quantity B a b

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
[Reveal] Spoiler: OA

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Re: a + b/10>0 [#permalink]  09 Jul 2018, 18:42
Carcass wrote:
$$a + \frac{b}{10} > 0$$

$$b + \frac{a}{10} < 0$$

 Quantity A Quantity B a b

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

My Anwer is A
GRE Instructor
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Re: a + b/10>0 [#permalink]  20 Aug 2019, 12:30
1
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Expert's post
Carcass wrote:

$$a + \frac{b}{10} > 0$$

$$b + \frac{a}{10} < 0$$

 Quantity A Quantity B a b

A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Take: $$a + \frac{b}{10} > 0$$
Multiply both sides by 10 to get: $$10a + b > 0$$

Take: $$b + \frac{a}{10} < 0$$
Multiply both sides by 10 to get: $$10b + a < 0$$
Multiply both sides by -1 to get: $$-10b - a > 0$$ [since I multiplied both sides by a NEGATIVE value, I had to REVERSE the direction of the inequality symbol]
Rearrange to get: $$-a - 10b > 0$$

We now have:
$$10a + b > 0$$
$$-a - 10b > 0$$

Since the inequality symbols are facing the SAME DIRECTION, we can ADD the inequalities to get: $$9a - 9b > 0$$
Divide both sides by 9 to get: $$a - b > 0$$
Add b to both sides to get: $$a > b$$

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Intern
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Re: a + b/10>0 [#permalink]  25 Aug 2019, 06:55
A
Re: a + b/10>0   [#permalink] 25 Aug 2019, 06:55
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