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# a ≠ –b

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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1783 [0], given: 397

a ≠ –b [#permalink]  15 Apr 2018, 04:34
Expert's post
00:00

Question Stats:

85% (00:30) correct 14% (00:01) wrong based on 7 sessions
a ≠ –b

 Quantity A Quantity B $$\frac{6a^2+12ab+6b^2}{(a+b)}$$ $$6(a+b)$$

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.

Drill 1
Question: 5
Page: 511
[Reveal] Spoiler: OA

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Sandy
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GRE Prep Club Legend
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1783 [0], given: 397

Re: a ≠ –b [#permalink]  18 Apr 2018, 15:44
Expert's post
Explanation

Whenever you see exponents, think common quadratics.

If you factor the 6 out of the numerator in Quantity A, you get $$6(a^2 + 2ab + b^2)$$, which includes a common quadratic $$(a +b)^2$$.

Then you can cancel (a + b) from both the numerator and the denominator; Quantity A is really just 6(a + b). The quantities are equal.
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Sandy
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Re: a ≠ –b   [#permalink] 18 Apr 2018, 15:44
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# a ≠ –b

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