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|a|/b > 1 and a+b<0

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|a|/b > 1 and a+b<0 [#permalink] New post 09 Aug 2018, 03:49
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80% (00:45) correct 19% (00:44) wrong based on 161 sessions
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Re: |a|/b > 1 and a+b<0 [#permalink] New post 09 Aug 2018, 15:31
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Carcass wrote:
\(\frac{|a|}{b} > 1\) and \(a+b<0\)

\(b \neq 0\)

Quantity A
Quantity B
a
0


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E



Given

\(\frac{|a|}{b} > 1\) and \(a+b<0\)

|x| is always positive.

So, b has to be positive.

but we know a + b <0. So, a has to be negative.

0 is greater than any negative value.

The best answer is B.
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Re: |a|/b > 1 and a+b<0 [#permalink] New post 23 Apr 2019, 06:08
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Expert's post
Carcass wrote:
\(\frac{|a|}{b} > 1\) and \(a+b<0\)

\(b \neq 0\)

Quantity A
Quantity B
a
0


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E


GIVEN: \(\frac{|a|}{b} > 1\)
In other words, \(\frac{|a|}{b}\) is POSITIVE
Since |a| must be POSITIVE, we know that b must also be POSITIVE


GIVEN: \(a+b<0\)
We already know that b is POSITIVE
Since the SUM a+b is negative, we know that a is NEGATIVE

We have:
QUANTITY A: some NEGATIVE number
QUANTITY B: 0

Answer: B

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Re: |a|/b > 1 and a+b<0   [#permalink] 23 Apr 2019, 06:08
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