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# |a|/b > 1 and a+b<0

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Founder
Joined: 18 Apr 2015
Posts: 13344
Followers: 288

Kudos [?]: 3382 [2] , given: 12176

|a|/b > 1 and a+b<0 [#permalink]  09 Aug 2018, 03:49
2
KUDOS
Expert's post
00:00

Question Stats:

79% (00:43) correct 20% (00:42) wrong based on 151 sessions
$$\frac{|a|}{b} > 1$$ and $$a+b<0$$

$$b \neq 0$$

 Quantity A Quantity B a 0

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

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Manager
Joined: 06 Jun 2018
Posts: 94
Followers: 2

Kudos [?]: 77 [2] , given: 0

Re: |a|/b > 1 and a+b<0 [#permalink]  09 Aug 2018, 15:31
2
KUDOS
Carcass wrote:
$$\frac{|a|}{b} > 1$$ and $$a+b<0$$

$$b \neq 0$$

 Quantity A Quantity B a 0

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

Given

$$\frac{|a|}{b} > 1$$ and $$a+b<0$$

|x| is always positive.

So, b has to be positive.

but we know a + b <0. So, a has to be negative.

0 is greater than any negative value.

GRE Instructor
Joined: 10 Apr 2015
Posts: 3830
Followers: 148

Kudos [?]: 4479 [3] , given: 69

Re: |a|/b > 1 and a+b<0 [#permalink]  23 Apr 2019, 06:08
3
KUDOS
Expert's post
Carcass wrote:
$$\frac{|a|}{b} > 1$$ and $$a+b<0$$

$$b \neq 0$$

 Quantity A Quantity B a 0

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

GIVEN: $$\frac{|a|}{b} > 1$$
In other words, $$\frac{|a|}{b}$$ is POSITIVE
Since |a| must be POSITIVE, we know that b must also be POSITIVE

GIVEN: $$a+b<0$$
We already know that b is POSITIVE
Since the SUM a+b is negative, we know that a is NEGATIVE

We have:
QUANTITY A: some NEGATIVE number
QUANTITY B: 0

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com
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Re: |a|/b > 1 and a+b<0   [#permalink] 23 Apr 2019, 06:08
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