Carcass wrote:
\(a > 0\)
Quantity A |
Quantity B |
\((a + a^{-1})^2\) |
\(a^2 + a^{-2}\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.
kudo for the right
solution and
explanationFrom Statement 1 , we have
\((a + a^{-1})^2\) = \((a + \frac{1}{a})^2\) = \((a^2 + \frac{1}{a^2}) +2\)
From Statement 2, we have
\(a^2 + a^{-2}\) = \(a^2 + \frac{1}{a^2}\)
From the two statement we find out that Statement 1 has number 2 added to \((a^2 + \frac{1}{a^2})\)
so for any values of a>0 , Statement 1 will always be greater than statement 2
Hence Option - A
_________________
If you found this post useful, please let me know by pressing the Kudos Button