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GRE Prep Club Legend  Joined: 07 Jun 2014
Posts: 4810
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
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A 6-sided cube has faces numbered 1 through 6. If the cube i [#permalink]
Expert's post 00:00

Question Stats: 50% (00:31) correct 50% (00:32) wrong based on 22 sessions
A 6-sided cube has faces numbered 1 through 6. If the cube is rolled twice, what is the probability that the sum of the two rolls is 8?

(A) $$\frac{1}{9}$$
(B) $$\frac{1}{8}$$
(C) $$\frac{5}{36}$$
(D) $$\frac{1}{6}$$
(E) $$\frac{7}{36}$$
[Reveal] Spoiler: OA

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Sandy
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GRE Prep Club Legend  Joined: 07 Jun 2014
Posts: 4810
GRE 1: Q167 V156 WE: Business Development (Energy and Utilities)
Followers: 118

Kudos [?]: 1899 , given: 397

Re: A 6-sided cube has faces numbered 1 through 6. If the cube i [#permalink]
Expert's post
Explanation

The probability of any event equals the number of ways to get the desired outcome divided by the total number of ways for the event to happen. Starting with the denominator, use the
fundamental counting principle to compute the total number of ways to roll a cube twice.

There are 6 possibilities (1, 2, 3, 4, 5, or 6) for the first roll and 6 for the second, giving a total of (6)(6) = 36 possibilities for the two rolls. For the numerator, determine the number of possible combinations that will sum to 8. For example, rolling a 2 the first time and a 6 the second time.

The full set of options is (2, 6), (3, 5), (4, 4), (5, 3), and (6, 2). Thus, there are 5 possible combinations that sum to 8, yielding a probability of $$\frac{5}{36}$$.
_________________

Sandy
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Try our free Online GRE Test Re: A 6-sided cube has faces numbered 1 through 6. If the cube i   [#permalink] 07 Aug 2018, 16:50
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