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a = 5b^2 – 10b + 7 [#permalink]
Expert's post 00:00

Question Stats: 62% (01:15) correct 37% (01:57) wrong based on 75 sessions

a = $$5b^2$$ – 10b + 7

 Quantity A Quantity B a b

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

_________________ Intern Joined: 08 Dec 2017
Posts: 40
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Kudos [?]: 43  , given: 70

Re: a = 5b^2 – 10b + 7 [#permalink]
2
KUDOS
a = 5b^2 – 10b + 7
let b=0, so a=7
b=1, a= 2
b=-1, a=22
So Q.A is greater. Manager Joined: 15 Feb 2018
Posts: 53
Followers: 1

Kudos [?]: 18  , given: 33

Re: a = 5b^2 – 10b + 7 [#permalink]
2
KUDOS
a = 5b^2 - 10b + 7
Subtract b from both sides
a - b = 5b^2 - 11b + 7
Since the coefficient of b^2 is positive the RHS is >0.

So a-b>0 --> a>b.

Intern Joined: 17 Feb 2018
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Kudos [?]: 2 , given: 2

Re: a = 5b^2 – 10b + 7 [#permalink]
gremather wrote:
a = 5b^2 - 10b + 7
Subtract b from both sides
a - b = 5b^2 - 11b + 7
Since the coefficient of b^2 is positive the RHS is >0.

So a-b>0 --> a>b.

great approach, didn't think of that Intern Joined: 11 Jan 2018
Posts: 44
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Kudos [?]: 37  , given: 7

Re: a = 5b^2 – 10b + 7 [#permalink]
3
KUDOS
It's a good question.

First need to simplify and then plugin as below:

Quantity A: $$5b^2$$ – 10b + 7
Quantity B: b

So, we can add 10b on both Quantities, because the inequality will not change i.e:

Quantity A: $$5b^2$$ + 7
Quantity B: 11b

Now, don't plugin -ve values, because Quantity A will always greater (being positive). Also in 0, Quantity A will be greater.
Finally, just check for positive values. You will see Again, Quantity A always greater.
For positive values, just plugin one value from (0 - 1) and other one from any value greater than 1.

Choice Choice A is correct.
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1 kudos = 1000 Thanks Re: a = 5b^2 – 10b + 7   [#permalink] 01 Mar 2018, 05:25
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