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Moderator  Joined: 18 Apr 2015
Posts: 5917
Followers: 96

Kudos [?]: 1158 , given: 5488

a > 1 and b > 5 [#permalink]
Expert's post 00:00

Question Stats: 81% (00:47) correct 18% (00:02) wrong based on 16 sessions
$$a > 1$$

$$b > 5$$

 Quantity A Quantity B $$(5b)^a$$ $$(b^2)^a$$

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

_________________ Director  Joined: 07 Jan 2018
Posts: 604
Followers: 7

Kudos [?]: 546  , given: 88

Re: a > 1 and b > 5 [#permalink]
1
KUDOS
Let us expand both quantities.
Starting with qty A

$$(5b)^a$$ can be re-written as $$5^a * b^a$$

qty B is equal to
$$b^2^a$$

Let us divide both sides by $$b^a$$; remember that $$b$$ is positive so when be is raised to any power the result will be +ve.

qty A will equal
$$5^a$$
while qty B will equal
$$b^a$$

Since $$b > 5$$ ; $$b^a$$ will always be greater than $$5^a$$ since a is also a +ve no greater than 1
_________________

This is my response to the question and may be incorrect. Feel free to rectify any mistakes Re: a > 1 and b > 5   [#permalink] 19 Jul 2018, 01:35
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