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a < 0 < b so compare ab and a+b [#permalink]
27 Oct 2016, 12:44

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Expert's post

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Question Stats:

56% (00:42) correct
43% (00:38) wrong based on 48 sessions

a < 0 < b

Quantity A

Quantity B

ab

a+b

A)The quantity in Column A is greater. B)The quantity in Column B is greater. C)The two quantities are equal. D)The relationship cannot be determined from the information given.

Re: a < 0 < b so compare ab and a+b [#permalink]
27 Oct 2016, 12:47

1

This post received KUDOS

Expert's post

Explanation

Plug in values for a and b. If a = −2 and b = 2, then Quantity B is greater. Eliminate choices A and C. If \(a=\frac{-1}{2}\) and \(b = \frac{1}{4}\), then Quantity A is greater. Eliminate choice B.

Hence option D is correct.
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Sandy If you found this post useful, please let me know by pressing the Kudos Button

Re: a < 0 < b so compare ab and a+b [#permalink]
21 Jul 2017, 02:47

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This post received KUDOS

I think the explanation is not properly written. Here it is given that a<0<b, then how can we assume the value of a as 1/2? if we take a=-1 and b=1, then Column B is greater. Again if we take a=-1 and b=1/2, then both the columns are equal, i.e, Column C So the answer will be D. Plz verify if possible

Re: a < 0 < b so compare ab and a+b [#permalink]
07 Mar 2018, 04:36

sandy wrote:

Explanation

Plug in values for a and b. If a = −2 and b = 2, then Quantity B is greater. Eliminate choices A and C. If \(\frac{1}{2}\) and b = \(\frac{1}{4}\), then Quantity A is greater. Eliminate choice B.

Hence option D is correct.

please add the minus before 1/2 or revise it not to create confusion
_________________

Re: a < 0 < b so compare ab and a+b [#permalink]
07 Mar 2018, 20:10

1

This post received KUDOS

correct: D a < 0 < b for comparing ab and a+b we can't do any simplifications. we know a is negative and b is positive.Thus, ab is always a negative value. but depending on the value of a and b, a+b can be either positive or negative. if |a| > |b| : ab is always negative and a+b is negative, so A > B if |a| <|b| : ab is always negative and a+b is positive, so A < B if |a| = |b| : ab is always negative and a+b equals zero, so A < B so based on the relationship between a and b and information, we can't figure out which one is less or more. the correct answer is D. _________________

Re: a < 0 < b so compare ab and a+b [#permalink]
03 Dec 2018, 04:44

FatemehAsgarinejad wrote:

correct: D a < 0 < b [b]for comparing ab and a+b we can't do any simplifications. we know a is negative and b is positive.Thus, ab is always a negative value. but depending on the value of a and b, a+b can be either positive or negative. if |a| > |b| : ab is always negative and a+b is negative, so A > B if |a| <|b| : ab is always negative and a+b is positive, so A < B if |a| = |b| : ab is always negative and a+b equals zero, so A < B so based on the relationship between a and b and information, we can't figure out which one is less or more. the correct answer is D.[/b]

Hi,

Fatima, refering to the highlighted part. I think we can simplify QTY A & B since B>0. We can divide b on both sides. It's a quesiton. I simplified it to get the answer b.

Re: a < 0 < b so compare ab and a+b [#permalink]
03 Dec 2018, 14:31

asfandiar wrote:

FatemehAsgarinejad wrote:

correct: D a < 0 < b [b]for comparing ab and a+b we can't do any simplifications. we know a is negative and b is positive.Thus, ab is always a negative value. but depending on the value of a and b, a+b can be either positive or negative. if |a| > |b| : ab is always negative and a+b is negative, so A > B if |a| <|b| : ab is always negative and a+b is positive, so A < B if |a| = |b| : ab is always negative and a+b equals zero, so A < B so based on the relationship between a and b and information, we can't figure out which one is less or more. the correct answer is D.[/b]

Hi,

Fatima, refering to the highlighted part. I think we can simplify QTY A & B since B>0. We can divide b on both sides. It's a quesiton. I simplified it to get the answer b.

Hello, By simplification I meant conversion between parameters of ab and a+b, for instance, if we had ab and a(b+1) we could.
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Re: a < 0 < b so compare ab and a+b
[#permalink]
03 Dec 2018, 14:31