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98^7

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98^7 [#permalink] New post 03 Jun 2017, 01:45
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions



Quantity A
Quantity B
\frac{98^7}{7^{63}}
\frac{2^7}{7^{49}}


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: 98^7 [#permalink] New post 27 Sep 2017, 05:05
Column A can be rewritten as \frac{7^{14}2^7}{7^{63}}=\frac{2^7}{7^{49}}. Thus, column A and B are equal and answer is C!
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Re: 98^7 [#permalink] New post 27 Sep 2017, 05:47
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IlCreatore wrote:
Column A can be rewritten as \frac{7^{14}2^7}{2^{63}}=\frac{2^7}{7^{49}}. Thus, column A and B are equal and answer is C!



The ans should be -

Column A & Column B is

\frac{{7^{14}2^7}}{{7^{63}}}=\frac{{2^7}}{{7^{49}}}

which comes to option C
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Re: 98^7 [#permalink] New post 28 Sep 2017, 04:43
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pranab01 wrote:
IlCreatore wrote:
Column A can be rewritten as \frac{7^{14}2^7}{2^{63}}=\frac{2^7}{7^{49}}. Thus, column A and B are equal and answer is C!



The ans should be -

Column A & Column B is

\frac{{7^{14}2^7}}{{7^{63}}}=\frac{{2^7}}{{7^{49}}}

which comes to option C


You are right, I made a typo!
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Re: 98^7 [#permalink] New post 06 Oct 2017, 15:07
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Carcass wrote:



Quantity A
Quantity B
\frac{98^7}{7^{63}}
\frac{2^7}{7^{49}}




We can solve this question using matching operations

Given:
Quantity A: (98^7)/(7^63)
Quantity B: (2^7)/(7^49)

Multiply both quantities by 7^63 to get:
Quantity A: 98^7
Quantity B: (2^7)(7^14)

Rewrite 7^14 as (7^7)(7^7) to get:
Quantity A: 98^7
Quantity B: (2^7)(7^7)(7^7)

A nice rule says (a^k)(b^k) = (ab)^k

Apply this rule to quantity B to get:
Quantity A: 98^7
Quantity B: (2 x 7 x 7)^7

Simplify to get:
Quantity A: 98^7
Quantity B: 98^7

Answer: C

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Re: 98^7   [#permalink] 06 Oct 2017, 15:07
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