We can solve this question using matching operations
Given:
Quantity A: \(8+ (6 \times \frac{1}{14})\)

Quantity B: \(8 + \frac{3}{7}\)


Subtract 8 from both quantities to get:
Quantity A: \(6 \times \frac{1}{14}\)

Quantity B: \(\frac{3}{7}\)


Evaluate and simplify to get:
Quantity A: \(6 \times \frac{1}{14}=\frac{6}{14} = \frac{3}{7}\)

Quantity B: \(\frac{3}{7}\)

Answer: C

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